Paper §4.2, Step 3(c): the per-step domination #
Paper: R-324 — §4.2 Step 3(c), one nested interval dominated by (4.4)
Step 3(c) of the paper, verbatim:
"For
[a₁, b₁]withk₁ = b₁ − a₁ + 1: the induced pairing is primitive, so (4.4) bounds the inner sum, which is exactlyJ̃_{k₁,prim}(x_{a₁} − x_{b₁})."
Three pointwise facts, all already proved elsewhere, make that a one-line estimate:
- the chain edge entering the interval is an admissible input,
|H(z)| ≤ |z|⁻²—exists_r324ReducedInput_admissible, which normalizes the §4.1 collapse so no constant survives; - the same for the edge leaving it;
- the inner sum on the block is bounded by the inserted majorant of (4.4)
—
proposition41_at_truncation.
Multiplying them is exactly the integrand r324Step3EightDimIntegrand of
Step 3(c), so integrating in the two block endpoints and applying
exists_r324Step3_elementaryEightDim_le removes the interval at the cost
of (Cλ)^{2k}·K. This is the single hypothesis
exists_r324Step3_nestedChain_le takes.
Step 3(c), pointwise.
The chain edge entering the removed interval, the inner sum on the
interval, and the chain edge leaving it are bounded respectively by
|u-a|⁻², the inserted majorant of (4.4), and |b-v|⁻². Their product is
therefore bounded by the Step 3(c) integrand.
Step 3(c), integrated in the two block endpoints.
The value carried by the interval before its removal is dominated by the elementary eight-dimensional integral at the interval's flanking pair. Both integrability premises are on the actual integrands, not on sections chosen after the fact.
Step 3(c), landed on the constant of Step 3(c).
Composing the previous domination with
exists_r324Step3_elementaryEightDim_le: the interval is removed at the
uniform cost (Cλ)^{2k}·K, which is the per-step hypothesis of
exists_r324Step3_nestedChain_le.